Question

What are the solutions of 6x2 - x - 15 = 0?

Answer 1

do u know the procedure for solving such problems?

Answer 2

no

Answer 3

ok shall i help u

Answer 4

\[6x^2 - x -15 = 0\]
this is the question .
just take the coefficient of first and the last term and multiply them

Answer 5

so the 6 and 15?

Answer 6

yeah multiply these two terms
always remember u have to multiply the co-efficients of first term that contains (variable ^2) and constant term

Answer 7

on multiplying 6 and 15 what do u get ????????

Answer 8

90

Answer 9

factorise it

Answer 10

-90

Answer 11

ignore signs

Answer 12

(x-3) (x+5)

Answer 13

That's not a good idea

Answer 14

Just think of two numbers that multiply to get -90 but add to get -1

Answer 15

-10 and 9

Answer 16

That's all you gotta do

Answer 17

no
90 = 2*3*3*5
then u have find such two numbers by mixing them which u will get middle term
here we get -10 & 9

Answer 18

okay now wat

Answer 19

Sheg what a surprise. You got the same thing I got

Answer 20

my bad

Answer 21

6x^2 - 10 x + 9 x -15 = 0

Answer 22

@ hero why surprised dear here in maths u always get the same answers not different

Answer 23

Now factor by grouping

Answer 24

6x^2 - 10 x + 9 x -15 = 0

First find the gcf for the first to terms: 2x
Then find the gcf for the last two terms: 3

2x(3x-5)-3(3x-5) = 0

Answer 25

gcf means greatest common factor

Answer 26

Next use the distributive rule to finish simplifying:

ab + ac = a(b+c)

In what we are trying to factor, a = 3x-5, b = 2x and c = -3:

so 2x(3x-5)-3(3x-5) = 0 becomes (3x-5)(2x-3)

Answer 27

Make sure you put (3x-5)(2x-3) = 0

Answer 28

Thanks lil lady

Answer 29

So whats the answer????