Question

Evaluate the following indefinite integral by using substitution:
\[\int\limits_{}^{}(\sin(2x+10)/\cos^2(2x+10))dx\]

Answer 1

u=cos(2x+10) and see what happens

Answer 2

\[-\frac{1}{2cos(2x+10)}\]
maybe

Answer 3

-2+1 = -1 so im sure that parts right lol

Answer 4

ghass: why can you set u to equal that? i thought u has to be something that is "inside a function"

Answer 5

let
\[2x+10=t\]
implies dx=dt/2
\[ \int\limits sint/2\cos ^{2}t dt\]
solve it basic integrations

Answer 6

\[\frac{1}{[...]}\]
is the inside of a function

Answer 7

ok so i actualy got what luckey got

Answer 8

should the next step be a substitution as well?

Answer 9

all subbing does is "clean things up" so they are easier to see

Answer 10

u is a function of x

u=cos(2x+10)
du=-2sin(2x+10)dx...

then your integral becomes (-1/2)*int(du/u^2) which is easy 2 compute

Answer 11

ah ok i see it ty guys

Answer 12

easy versus familiar ...

Answer 13

I got positive amistre's answer\[-{1\over2}\int\limits {du \over u^2}={1\over2u}+C={1\over2\cos(2x+10)}+C\]
Ghass' techinique is correct

Answer 14

then read it as \[1/2 \int\limits \tan(t) \sec(t)dt\]
which is equal to
\[1/2sect\]
substitute the value of t
u get 1/2sec(2x+10)

Answer 15

accursed signs lol

Answer 16

i got the same answer as test got........

Answer 17

yes and used a very different method :)