Question

8^x+3=16^x−1
solve the exponential equation

Answer 1

\[8^{(x+3)} = 16^{(x-1)}\]
Let the base equal.
\[2^{(3x+3)} = 2^{4(x-1)}\]
Then, just set the exponents equal to each other.
\[3(x+3) = 4(x-1)\]
\[3x+9 = 4x - 4\]
\[4x-3x = 9+4\]
\[x = 13\]

Answer 2

thanks dear

Answer 3

I was trying to solve the one he wrote and I was going INSANE... lol...!

Answer 4

Fix :: \[2^{3(x+3)} = 2^{4(x-1)}\] **

Answer 5

\[8^x -16^x +4\]
I was searching solutions for this one :D...!

Answer 6

hahahaha @alfie

Answer 7

i guess i posted it the wrong way?!

Answer 8

It should have been written as:
8^(x+3)=16^(x−1)

It is clearer.

Answer 9

ok thanks