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4^(x+3)=16
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\[4^{(x+3)}=16\]
x=1
would be the answer
4^?=16
???
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4^2=16
so\[ \log_416=2\]not 4...
now what do you get?
i have no idea... you kinda lost me
x+3=2 x= -1
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yes
\[\log_4(4^{x+3})=\log_416\]\[x+3=2\]\[x=-1\]
oh i get, i over though the question
happens all the time :)
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