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Mathematics 14 Online
OpenStudy (anonymous):

consider a triangle where A=30 degrees, a=1.5cm and b=2.8cm Use the law of sines to find sin(B).

OpenStudy (alfie):

Well... it's pretty simple. Just apply the formula... \[a/sinA = b/sinB\] To get: 1.5/sin30 = b/sinB. Now is just an equation.

OpenStudy (alfie):

1.5/sin30 = 2.8/sinB :)

OpenStudy (anonymous):

So would my calculator be best in degrees? If so I got 1.5/sin30 as 3 Is this correct so far?

OpenStudy (alfie):

yes... 3 = 2.8/sinb => 3sinb = 2.8 => sinb = 2.8/3 .

OpenStudy (anonymous):

sinb=2.8/3 which is .93333333 or .93?

OpenStudy (alfie):

sinB = .93333... Now type in the number in your calculator and press "sin" ;).

OpenStudy (phi):

I'm sure he means inverse sin

OpenStudy (anonymous):

i'm not getting an answer on ti83+ when i enter the .93333 and then hitting sin

OpenStudy (anonymous):

inverse sin(.93333) = 68.959 or 68.96

OpenStudy (phi):

Looks good. You can always check: a/sinA =b/sinB it should work (it will)

OpenStudy (anonymous):

Thank you phi and alfie for all your help. :)

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