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OpenStudy (anonymous):
consider a triangle where A=30 degrees, a=1.5cm and b=2.8cm
Use the law of sines to find sin(B).
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OpenStudy (alfie):
Well... it's pretty simple. Just apply the formula...
\[a/sinA = b/sinB\]
To get:
1.5/sin30 = b/sinB.
Now is just an equation.
OpenStudy (alfie):
1.5/sin30 = 2.8/sinB
:)
OpenStudy (anonymous):
So would my calculator be best in degrees? If so I got 1.5/sin30 as 3 Is this correct so far?
OpenStudy (alfie):
yes... 3 = 2.8/sinb => 3sinb = 2.8 => sinb = 2.8/3 .
OpenStudy (anonymous):
sinb=2.8/3 which is .93333333 or .93?
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OpenStudy (alfie):
sinB = .93333... Now type in the number in your calculator and press "sin" ;).
OpenStudy (phi):
I'm sure he means inverse sin
OpenStudy (anonymous):
i'm not getting an answer on ti83+ when i enter the .93333 and then hitting sin
OpenStudy (anonymous):
inverse sin(.93333) = 68.959 or 68.96
OpenStudy (phi):
Looks good.
You can always check:
a/sinA =b/sinB
it should work (it will)
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OpenStudy (anonymous):
Thank you phi and alfie for all your help. :)
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