Question

@Chemistry
4C3H5(NO3)3-->12CO2+10H20+6N2+O2
How many grams of carbon dioxide are produced by the explosion of 21.0 grams of nitroglcerine?

Answer 1

n = m/M.
n = mols of the substance.
m = mass of the substance.
M = molar mass of the substance.

Now what you want to do is find the mols of nitroglycerine.
So, n = m/M.
Now we need m and M.
m = 21.0 g (in the question).
M = ?

To find M, look at the periodic table or use your memory to determine it.
For example N corresponds to 14.0 g/mol.

After you have found n, look at the equation.
You see that for every single of nitroglycerine you have 12 CO2 particles.

So find n for nitroglycerine, and multiply that by 12.

Rearranging the equation:
n = m/M
We want m of CO2.
m = n x M.

Find M of CO2 (44.0 g/mol).

Do the calculation.