Question

Given the following function,
(a) find the domain,
(b) determine the vertical asymptote.
(c) submit the graph of the function
Please be sure to show all of your work.
y = log(-x)

Can someone please help me. Thanks.

Answer 1

First of all note that the argument of a log function cannot be negative so (-x) >0 or x<0. That is the domain . Get some ordered pairs to draw the graph. 10^y=-x so it might be helpful to choose the y value and calculate the x from that. if y = 0 1=-x so x = -1
x y
-1 0
-10 1
-1/10 -1
Plot the points and draw the graph. Since x cannot be positive the y axis is a vertical asymptote
The Range is all real numbers

Answer 2

a) \[x \le0\]
b) x=0
c)

Answer 3

x=0 cannot be included in the domain

Answer 4

Correction strictly less than.

Answer 5

what is the equation I put on this graph?

Answer 6

so the vert asymptote would be y=0?

Answer 7

x=0 is the vertical asymptote.....y=0 is a horizontal line.

Answer 8

A good way to know is to visualise the graph. Try to learn what a log function looks like, then notice how the -x makes it reflected in the y-axis. The asymptote is always at x = 0 unless of factors such as translation.

If you reflect x = 0 in the y-axis it is still the same thing.

Answer 9

ok- im trying to get this to graph on my calculator, but what is the equation i would put in?

Answer 10

Which graph do you want?

Answer 11

Put in \[Y=Log[-x]\]
make sure your windows shows values for negatives x's.

Answer 12

thank you!!