Graph the following piece wise function. State the values for f(0) and f(-2). Please show all of your work and submit graph. f(x)={x^2-3 if x>-2@ 3 if-5 ≤x< -2@-x+3 if x< -5)
Piece wise functions are very simple. You just evaluate f(x) for a certain function depending on what range x falls into. \[\Large f(x) = \left\{ {\begin{array}{*{20}{c}} {x > - 2}&{}&{{x^2} - 3}\\ { - 5 \le x \le - 2}&{}&3\\ {x < - 5}&{}&{ - x + 3} \end{array}} \right.\] Just start an arbitrary x value to one side of the piecewise function, and increment (or in this case decrement) x by 1 re-evaluating at each point. So when... x = -1, f(x) = x^2 -3 = (-1)^2 - 3 = -2, so plot a point at (-1,-2). x = -2, f(x) = 3, plot (-2,3) x = -3, f(x) = 3, plot (-3,3) x = -4, f(x) = 3, plot (-4,3) x = -5, f(x) = 3, plot (-5,3) x = -6, f(x) = -x+3 = -(-6) + 3 = 0, plot (-6,9) And so on.
is this the answer that I should use?
can you show the graph?!
No, because it's REAL hassle to try and get a graph on here. Can't you just plot the graph yourself?
yes but what is the input so I can plot it?
I havent quite figured out how to input it into wolphram alpha
Well... the function is piece wise, so it depends on what range the input falls into. There's three functions to plot: f(x) = x^2 - 3, f(x) = 3 and f(x) = -x + 3 but at which point you plot them depends on what the value of x is at that point. I really can't explain it any better than that.
ok
im just wondering how to type that into the calculator
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