Question

Given the equation x^2+y^2-8x-6y=0
(a) Write the equation in standard form.
(b) State the center, radius, and intercepts.
(c) Submit the graph..
Please show all of your work.

Answer 1

medal plsss

Answer 2

:)

Answer 3

answer please. LOL

Answer 4

http://www.wolframalpha.com/input/?i=x%5E2%2By%5E2-8x-6y%3D0

Answer 5

now giv medal lol

Answer 6

(a) Write the equation in standard form.
(b) State the center, radius, and intercepts.

Answer 7

(a)\[(x-4)^2-16+(y-3)^2-9=0\]\[(x-4)^2+(y-3)^2=25\]

Answer 8

center (4,3)
radius 5

Answer 9

sarah lets share the medal

Answer 10

lolz

Answer 11

lol share?

Answer 12

Sarah- so is the y-intercept -3 and the x-intercept -4 ?

Answer 13

no
the center is (4,3)
for the intercepts you substitute y=0 and solve for x
then substitute x=0 and solve for y

Answer 14

Thanks Sarah!! :)

Answer 15

your welcome:)

Answer 16

srry u see the ntercepts are in the fig i gave

Answer 17

pls giv medal

Answer 18

Aravind- how do i know your answer is correct? lol

Answer 19

:( its correct wolfranpha never goes wrong

Answer 20

haha- ok then- thank you...