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Mathematics 15 Online
OpenStudy (anonymous):

At alpha =0.05 can you support the claim that the proportion of men living in parents homes was greater in 1995 than in 2004? Assume the survey included 12,100 men and 12,300 women in 1995, and 14,400 men and 14,800 women in 2004. The % of men in 1995 is 54.9% and the % of women is 47.8%. In 2004 the % of men is 49.5% and the % of women is 48.5%...

OpenStudy (anonymous):

I dont want the answer right now im just trying to figure out how i can find my x sub 1 and x sub 2

OpenStudy (amistre64):

is it a normal distribution?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

At alpha =0.05 "the proportion of men living in parents homes was greater in 1995 than in 2004" 1995: 12,100 men ; 54.9% 12,300 women ; 47.8%, 2004: 14,400 men ; 49.5% 14,800 women ; 48.5%... this might clean up the clutter better

OpenStudy (anonymous):

ok i got that far but how do i find my x sub 1 and 2 i guess thats my main problem

OpenStudy (anonymous):

multiply the % by the N of both men and women?

OpenStudy (amistre64):

dunno, what does this mean: " The % of men in 1995 is 54.9% " is that how many lived at home with mommy and daddy?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

i cant recall enough bits and pieces at the moment to determine a suitable answer .....

OpenStudy (anonymous):

ok thank you

OpenStudy (amistre64):

can we assume that the 54.9% relates to the area under the curve to the left of the "zscore" for that year?

OpenStudy (anonymous):

Im not sure all I know is Im making a right tailed test because my alternative hypothesis is a greater than..

OpenStudy (anonymous):

i need x1, x2, n1, n2

OpenStudy (anonymous):

im assuming my n's are the number of men in each year that lived at home

OpenStudy (amistre64):

sounds good, but if this can wait; and noone else comes up with a better answer; ill read up on the parts im forgetiing and see what I can deduce ;)

OpenStudy (anonymous):

your amazing thank you

OpenStudy (amistre64):

from what i can gather so far, this is a hypothesis testing on a two sample proportion. Are you using a calculator, like a ti83?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

once i find what x1,x2,n1,n2 is i can input the info

OpenStudy (amistre64):

then i believe: x1 = 12100(.549) and n1=12100 x2 = 14400(.495) and n2=14400 X = number observed, and N = total sample.

OpenStudy (amistre64):

the score for a=.05 is: 1.645

OpenStudy (anonymous):

i put that in the calculator and it gives me a domain error

OpenStudy (amistre64):

hmmm, its prolly the decimal; try rounding the Xs up to the next whole integer

OpenStudy (anonymous):

omg your a genius

OpenStudy (amistre64):

12100(.549) = 3294.225 -> 3295 would be a proper proportion

OpenStudy (anonymous):

something so small and all i had to do was round lol

OpenStudy (anonymous):

yep im in love thank you so much for helping me with that

OpenStudy (amistre64):

youre welcome, hope it helps, and that its right lol

OpenStudy (anonymous):

it is right thank u!!!

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