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solve ^3sqrt2x+4+9=1
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please type correctly...
|dw:1321816114982:dw|
the 9 is not under the thing
-258
\[\sqrt[3]{2x+4}\] = 1-9 \[\sqrt[3]{2x+4}\] = -8 \[\sqrt[3]{2x+4}\] = -1 * 8 \[\sqrt[3]{2x+4}\] = -1 * \[\sqrt[3]{8}\] 2x+4 = -1 * 2 2x + 4 = -2 2x = -6 x = -3
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How can cube root of 2x+4 be equal to -1*8 and -1*cube root of 8?
-8 is'nt cube root
If x is substituted as -3, then the answer doesn't result to 1. Check your calculations again.
then show ur steps
|dw:1321806150091:dw|
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