What does the following code do? #include int main(void) { int i, j, k; for (i = 0; i

Question

What does the following code do?

#include <stdio.h>

int main(void)
{
    int i, j, k;
    for (i = 0; i < 10; ++i) {
        for (j = 0; j < 10; ++j) {
            for (k = 0; k < 10; ++k) {
                printf("%d%d%d
", i, j, k);
            }
        }
    }
	return 0;
}

anonymous · Answer

It prints a table of values, where the values could be represented in a 3-dimensional table

anonymous · Answer

It generates numbers between 100 and 199.

anonymous · Answer

100 and 999

anonymous · Answer

Sorry. Yes! Mistyped. :-)

anonymous · Answer

http://ideone.com/uRi0l

anonymous · Answer

000 and 999 :-D

anonymous · Answer

hmm yeah I was thinking about because it is ++i not i++

anonymous · Answer

Yes....same here. Increment happens before the test I thought in the way it was written. God it has been 12 years since I coded. So, I may be wrong.

anonymous · Answer

hmm good point I made it a habit to write ++i instead of i++ in my loops, but I never figured it would make a difference in the final part of a for-loop. Let me see what happens if I make it post-increment http://ideone.com/y7htD No change :(

anonymous · Answer

Interesting. I always wrote it as i++ back in the days.