the length of a rectangle is 3 times the width. the perimeter is 96 cm. find the width and length.
L = 3W 2L + 2W = 96 Solve simultaneously and you get l=36, w=12
sheg how did you get that
Sheg's answer clearly isn't right since the perimeter of such a figure is not 96
moneybird's answer is also not right
That is given
yes they are wrong
it should be 4w = 48 so w = 12 length = 36
l=36, w=12 as I said in my original answer
ktklown you are right how did u get that
The length is 3 times the width, so L=3W The perimeter is the sum of the four sides, two lengths and two widths. 2L + 2W = 96 Then you solve simultaneously.
Since L=3W, substitute that into the 2nd equation 2(3W) + 2W = 96 6W + 2W = 96 8W = 96 W = 12
yeah in hurried ness i divided 96 by 16 instead of 8 so uit should be 96/8 = 12 so width = 12 length = 36
how do u find the length
L=3W
In general once you've solved for one variable in a system of two equations, just plug that value into either of the other two equations (whichever looks easier)
You have two equations, L=3W and 2L+2W=96. Once you have W you just plug the value for W into either one of those equations and solve.
so can you please solve 2l+ 2w= 96 please
What part are you having trouble with
finding the lenght
So substitute the width into either equation. The other equation is probably easier.
can u please show me how it is supposed to look please
Take the equation you had, L=3W and substitute in W=12
can u just solve it for me cuz i dont understand
do you know what "substituting" means?
yes
OK so can you substitute W=12 into the equation L=3W?
ok
what do you get
36
thats the answer
thank you
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