Question

Rationalize the denominator of 9/(7-3√3)-(6-4√3)

Answer 1

is it:
(9/x) - y
OR:
9/(x-y)

Answer 2

\[\frac{9}{7-3√3}-(6-4√3)\]or:
\[\frac{9}{(7-3√3)-(6-4√3)}\]

Answer 3

Oh the second one sorry was trying to understand how to do it

Answer 4

ok, so this the the expression you want to rationalize, correct?
\[\frac{9}{(7-3√3)-(6-4√3)}\]

Answer 5

Correct

Answer 6

$$ \frac{9}{1+\sqrt{3}} $$

Answer 7

ok, first simplify the denominator:
\[\frac{9}{(7-3√3)-(6-4√3)}=\frac{9}{7-3√3-6+4√3}=\frac{9}{1+\sqrt{3}}\]

Answer 8

well now you could rationalize ..

Answer 9

you can then remove the radicals from the denominator by noting that:\[a^2-b^2=(a+b)(a-b)\]

Answer 10

Lol thanks to both of you

Answer 11

glad to help :)

Answer 12

so you can multiply the numerator and denominator by:\[(1-\sqrt{3})\]

Answer 13

I assume you are ok from here on?

Answer 14

Yes thanks again :)

Answer 15

yw