Question

Use the Quadratic formula to solve the equation. Simplify any radicals...x2=7-4x

Answer 1

if you bring everything to one side to make it simpler it would be x^2 + 4x - 7 =0

Answer 2

now just plug that into the quadratic formula. do you have the formula memorized?

Answer 3

i do

Answer 4

alright, so what would the quadratic formula for that equation look like?

Answer 5

how do i right it in?

Answer 6

-b+-sqare root b2-4ac all over 2a

Answer 7

first lets find out what our a, b, and c are:

since we have x^2 by itself we know a = 1

since we have 4x as our second term our b = 4

and -7 is our last term so we have c = -7

so now plug that into your formula

Answer 8

-2+-sqare root 11?

Answer 9

you should get something that looks like this:
\[-4\pm \sqrt{(4)^2 - 4(1)(-7)} \over 2(1)\]

Answer 10

yup

Answer 11

yeah, you got it! -2 +- sqrt(11) is right! i'm pretty impressed, most people who come here just want answers, you have my respect good sir/madam

Answer 12

thanks! I am trying to get them right! =)

Answer 13

Thanks for your help!

Answer 14

well you are doing a good job of it so far!! :)

Answer 15

no problem! glad i could be of service!

Answer 16

i just thought everything had to be positive thats where i was getting confused

Answer 17

nope, you are allowed to have negatives wherever you want, it just starts getting funky when they are underneath the square root. but i'm sure you'll learn about that soon enough. :)

Answer 18

if i have another question do i ask it here or do i repost it?

Answer 19

you can ask here if you like, or repost, it's really up to you. i'd be glad to help you with another one either way.

Answer 20

ok cool thanks!...its a complex fraction...

Answer 21

bring it on! lol

Answer 22

\[9 + 3/x \over x/4 + 1/12\]

Answer 23

so far i have all the work down to \[12(9x+3) \over x(3x+1) \] and then I get lost...

Answer 24

are you just supposed to be reducing it?

Answer 25

the directions are to simplify..

Answer 26

ok, sounds good, you are almost done actually! the trick here is to get rid of the (9x+3) and (3x+1)

Answer 27

i have 9x+ 3 over x Multiplied by 12 over 3x+1?

Answer 28

you can do this by factoring a 3 out of the (9x+3) which will give you 3(3x+1)

since you have the same thing on the bottom you can cancel both of them

Answer 29

so it it 36 over x?

Answer 30

so it will look like: \[12(3)(3x+1) \over x(3x+1)\]

Answer 31

yup, when you cancel and multiply that is exactly what you get.

Answer 32

ok I was ending up with an extra 3 thats why I wasn't sure! thanks

Answer 33

no problem! glad i could help you work that one out.

Answer 34

I have a couple more if you're not to busy...