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Mathematics 8 Online
OpenStudy (anonymous):

How do I write an equation for: 7, 7.5, 7.75, 7.875, ...? Do I use the geometric sequence formula or recursion formula? Please help!

OpenStudy (anonymous):

And be able to determine the 8th term?

OpenStudy (kinggeorge):

This looks like a geometric sequence to me\[7, 7+{1 \over 2}, 7+{1 \over 2} +{1 \over 4}, 7+{1 \over 2} +{1 \over 4}+{1 \over 8},...\]

OpenStudy (anonymous):

hmm..

OpenStudy (kinggeorge):

8th term would then be\[6+\sum_{i=0}^{7}{1 \over {2^i}}\] I'm using 6 since the first term is 7, or 6+1

OpenStudy (anonymous):

what's the big E? o.O

OpenStudy (anonymous):

isn't the geometric formula: tn = a*r^n-1

OpenStudy (kinggeorge):

It's a summation symbol, just a different notation. In terms of the geometric formula, you're adding \[{1}*{({1 \over 2})^{n-1}}\] to 7 each time.

OpenStudy (anonymous):

ohhh.. i see.

OpenStudy (anonymous):

still kind of iffy about it..

OpenStudy (kinggeorge):

Since you're adding things, to get the actual n-th term, you would need to use the summation symbol I used previously. Basically, you increment the i from 0 to 7 and add up all the terms.

OpenStudy (anonymous):

ohhh :P okay!

OpenStudy (kinggeorge):

If you were looking for an explicit formula to get the 8th term, I don't know how to get it.

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