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OpenStudy (anonymous):

What are the oxidation numbers for Pb , S & O in the equation Pb(SO4)2 ? [I have already tried solving this, just wondering if I got answers right]

OpenStudy (anonymous):

pb 2+

OpenStudy (anonymous):

How did you get that, if you do not mind me asking?

OpenStudy (anonymous):

My bad, its actually Pb4+ (SO4)2- then you have Pb2(SO4)4 then you reduce and get Pb(SO4)2

OpenStudy (anonymous):

Ok, thank you so much ! (:

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