Does the series converge or diverge? \[\sum_{1}^{infinity}\frac{\sqrt{n}}{n+1}\]
Notice that \[ \frac{\sqrt{n}}{n+1} > \frac{1}{n+1} \] Now does the infinite sum of the terms on the right converge?
Oh ok the right one diverges (similar to the harmonic one).. so the left one diverges by comparison test right?
yes
ok thanks :)!
jamesj is exactly right, but with a little practice you do this with your eyeballs. degree of numerator is 1/2 and denominator is 1 if the degree of the denominator does not exceed the degree of the numerator by more than one it diverges. i will be willing to bet that is what jamesj thought (correct me if i am wrong) before he wrote the answer
our prof won't allow us to "eyeball" stuff.. we have to show exactly each step -_-
sat73 is right; I know that heuristic and used it here first. It's a convenient rule to have. Knowing now what the answer 'should be', I decided what was the best way to prove it. The method I suggested and you're now using is my estimation definitely the most elementary.
Join our real-time social learning platform and learn together with your friends!