List all possible rational zeros for the polynomial below. Find all real zeros of the polynomial below and factor completely. Please show all of your work. f(x) = 3x^4+17x^3+17x^2-33x-36
I might not answer, but it might help others who want to help you if you showed any work you did so far.
What does the rational root theorem say about the possible real roots of a polynomial?
we need to find all the factors of −36 (coefficient of x0) and all the factors of 3 (coefficient of x4) factors of −36:±1,±2,±3,±4,±6,±9,±12,±18,±36 factors of 3:±1,±3 possible rational roots are: ±1/1,±2/1,±3/1,±4/1,±6/1,±9/1,±12/1,±18/1,±36/1 ±1/3,±2/3,±3/3,±4/3,±6/3,±9/3,±12/3,±18/3,±36/3 We simplify and remove all the duplicates. The list of all possible rational roots is: ±1/3,±2/3,±1,±4/3,±2,±3,±4,±6,±9,±12,±18,±36 The following are the roots: −3,−1,43 The equation can be written as follows: (x+1)(x+3)(x+3)(3x-4) Is this correct?????
Maybe show your steps?
that's 4/3 not 43 btw
Step 1: Find a root by trying various x, until f(x) = 0 (they must be factors of -36) Step 2: Divide the corresponding factor (x - root) into f(x) to get a new polynomial. Step 3a: If there are still x in your new f(x), go back to step 1. Step 3b: If there are no x in your new f(x), you have found all the roots (zeroes).
looks good to me, just let me multiply out your equation to be sure...
ok
yup, looks perfect!
Thanks TuringTest :)
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