Question

how to differentiate -cos x^3 x^2??

Answer 1

use product rule

Answer 2

please write with brackets. Cant really tell what is what

Answer 3

u(x)P(x)=u'(x)p(x)+u(x)p'(x) in you in your case you may set -cosx^3 as u(x) and
p(x) as x^2

Answer 4

so when differentiate -cos^3, we get -sin^3?? is it?

Answer 5

is the equation supposed cos(x^3) or (cosx)^3

Answer 6

?

Answer 7

\[\cos ^{3}\]

Answer 8

which one you are still not clear

Answer 9

-cosx^3 or -cos(x^3)
?

Answer 10

\[\cos ^{3}=-\sin ^{3}\] is it true?

Answer 11

which one of these two the first one the second one?

Answer 12

no, im answering the ques. i asked what is the answer after defferentiate \[\cos ^{3}\],, so is it true that after differentiate i get \[-\sin ^{3}\]?

Answer 13

no

Answer 14

wrong

Answer 15

because when -3cosx^2

Answer 16

hey what happened to you

Answer 17

i dont get wht ur saying

Answer 18

-cosx^3 = sinx^3

Answer 19

i have check and the answer actually -3 cos x^2 (-sin x),,, but tanx btw