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OpenStudy (anonymous):
@chemistry The value of the equilibrium constant, Kc, for the reaction to form ethyl ethanoate from ethanol and ethanoic acid is 4.0 at 60 °C. C2H5OH + CH3CO2H (eqilibrium sign) CH3CO2C2H5 + H2O When 1.0 mol of ethanol and 1.0 mol of ethanoic acid are allowed to reach equilibrium at 60 °C, what is the number of moles of ethyl ethanoate formed?
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