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y=50/(1+6e^-2t) Find the critical points
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for x is greater than 0
whoops for x greater or equal to zero
\[y = \frac{50}{1+6e^{-2t}}\] take the derivative to respect t and you'd find:\[y' = \frac{600e^{2x}}{(e^{2x}+6)^2}\] equal it to 0 (zero), solve it and you'll find the CP. did that help ?
mathmind what will be the value for mass in that question?
I know that but i want to see what u got
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This function has no critical points, it is never zero.
That is wht i got
the derivative, i mean, is never zero, or undefined for that matter.
I guess it just has a saddle point
you need DNE for saddle points.
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ok thnaks
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