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Mathematics 14 Online
OpenStudy (anonymous):

A sprinter accelerates uniformly to his top speed after running 30 metres of a 100 metre race. He maintains this speed for the reminder of the race and takes 10.4 seconds to complete it. Find: a) the top speed of the athlete b) the time taken to reach the top speed

OpenStudy (anonymous):

b) 4.8 seconds..

OpenStudy (anonymous):

top speed is 12.5 metres/second..

OpenStudy (anonymous):

do i have to explain?

OpenStudy (anonymous):

yes please

OpenStudy (anonymous):

i got the same answer

OpenStudy (anonymous):

i got this by visualizing the problem as a graph of velocity over time... |dw:1321869269214:dw|

OpenStudy (anonymous):

so there's a plot of velocity over time. uniform acceleration until a time I'm calling T30 (the time at which he reached 30 meters), at a velocity of Vmax. You know since this is a V-T curve, the area under the curve is the distance travelled. And you know the equation for area in a triangle is 1/2 b*h, and a rectangle is just l*w. knowing all this I set up 2 equations: 0.5 * T30 * Vmax = 30 (the area of the initial triangle is 30) (10.4-T30)*Vmax = 70 (the remaining time he ran the race at a constant speed of vmax, he covered 70 meters, since the race was 100 meters total) Solve those two equations simultaneously and you get T30 = 4.8 Vmax = 12.5.

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