Question

who can help me with my calculus assignment? thank you

Answer 1

what is it

Answer 2

find the equation of the tangent line to the graph of y=x^3 and s parallel to the line 3x-y+1=0.

Answer 3

ok so what are the two things you need to know to define a line?

Answer 4

no,on how can i find the point of that equation.

Answer 5

i don't understand what you said. your goal here is to find a particular line, so my first question is, what two pieces of data do you need to uniquely define a line?

Answer 6

im sorry, but our objective here is just to find the tangent line. so i'm asking on how i can find the point of x and y.

Answer 7

I don't think you understood my question. the two things you need to find a line are its slope, and a point on it, right?

Answer 8

yes..exactly..that is my problem...because in that equation/problem we are the one who should find the slope and the point..

Answer 9

I know that, that's what I'm trying to help you do. So first let's find the slope. it's parallel to the line given in the second equation so how do you find that slope?

Answer 10

we should find the point of x and y..i think..

Answer 11

do you know how to find the slope of a line, given the standard equation y=mx+b?

Answer 12

you can't find the point until you know the slope monique

Answer 13

you know how you find the slope when you use the derivative and a point given? well, you have to work back from it

Answer 14

you have to find the slope which will give you a f'(x) at the certain point in which you solve for x

Answer 15

so first find the slope of the line. do you know how to?

Answer 16

y=3x+1

m=3 correct?

Answer 17

i think i forgot it already..sorry..haha...because we use this formula: m=yprime=derivatives of the equation..

Answer 18

so now you know that f'(x)=3

Answer 19

just take the line parallel and put it into y intercept form or y=mx+b

Answer 20

where m = slope

Answer 21

and?

Answer 22

okay so if you want to use derivatives, then find the first derivative of y=3x+1 in order to find the slope of that line

Answer 23

then differentiate your original f(x), solve f'(x) = m (where m is the slope), then plug in that x value to f(x) to find the y value. then you have a point and a slope and you can find the equation of the tangent line.

Answer 24

your slope will be m=3

now that you have the slope of the line, you need to recall that the first derivaitve is the slope at a given point

Answer 25

did any of that make any sense?

Answer 26

yes..just proceed your discussion:)

Answer 27

we already described in detail how to solve hte problem, now it's your turn to do the work to find the solution

Answer 28

so step one is find the slope of your desired tangent line by taking the first derivative of the line it's supposed to be parallel to

Answer 29

can you do that?

Answer 30

so diffrentiate your function you are trying to find the tangent line to (y=x^3)

f'(x)=3x^2
and since we know that the slopes of parallel lines are the same, the slope of the line and the derivative of the curve(which will equal the slope of the tangent), we can substitute

f'(x)=3 into f'(x)

3=3x^2

divide by 3

1=x^2

square root
+-1=x

Answer 31

monique i kind of feel like you're not really trying here

Answer 32

are you there?

Answer 33

use the point 1 as it's easier and y-y1=m(x-x1)

monique, if you are in calc 1, i can assure you a lot that you are learning right now carries throughout all of calculus, so you can't just go right through this. Calc 1 is the fundamentals and Calc 2/3 are going deeper into what you learned of Calc 1

Answer 34

outkast - it's funny there's actually a slight bug in the problem, it asks for "the" tangent line but there are two solutions; it should have asked for "a" tangent line

Answer 35

outkast and ktklown, i'm sorry for late reply..i'm trying to understand..

Answer 36

thanks for helping i get it already..thank you..

Answer 37

ok...

Answer 38

the final answer hasn't actually been computed yet in this chat