Question

Observation suggest that for herbivorous mammals, the number of animals N per sq.km can be estimated by the formula N=91.2/M^0.73 where M is the average mass of the animal in kilograms. USING THIS FORMULA, IT IS ESTIMATED THAT THERE IS LESS THAN ONE ANIMAL OF A CERTAIN SPECIES PER SQ.KM. HOW LARGE CAN THE AVERAGE ANIMAL OF THIS SPECIES BE? C. ONE SPECIES OF LARGE MAMMAL HAS TWICE THE AVERAGE MASS AS A SECOND SPECIES. IF A PARTICULAR RESERVE CONTAINS 100 ANANIMALS OF THE LARGER SPECIES, HOW MANY ANIMALS OF THE SMALLER SPECIES WOULD YOU EXPECT TO FIND THERE?

Answer 1

crap

Answer 2

Well for part one, in the boundary condition, N=1, so solve 1=91.2/M^0.73

Answer 3

so what's the answer?

Answer 4

do you know how to solve for M in that case? what's the first step towards isolating M?

Answer 5

idk