A cube with a mass of 2.5 kg slodes down from the top of a frictionless ramp 1.5m high. The ramp is 32.6 degrees with respect to the horizontal. What is the work done by the force exerted by the cube when it reaches the bottom of the ramp?

Question

fretje · Answer

E = m.g.h   (potential energy equals mass times gravitational acceleration times height)
W = Epot+Ekin = Epot + 0 (the cube was motionless initially)
W = m.g.h = 2.5kg.9.81m/s².1.5m = 36.7875 Joule (kgm²/s²)

You don't need the slope angle data.