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If volume of a sphere is increased by 72.8% then by what % its surface area will increase?
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consider sa = v r^2 = r^3 if v is increased by 72.8, then R= cube root under 1.728r so sa= R^2 = (cube root under 1.728r)^2 = 1.44r thus surface area will increase by 44%
saruz ! if sa = v then how r^2 = r^3 because sa = 4 pie r^2 and v = 4/3 pie r^3
saruz reply soon.....
that is not true at all ........that is the thing you need to do in rough.....its just a fast method of doing mathematics..... sa never = v but sa (three equal to sign) v
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that is an assumption!
did i get the answer wrong?>
your ans. is right but after assumption when we equal sa and v then (see fig.)|dw:1321882631359:dw|
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