This question is from Calc 3 and is most likely for people who have had calc-based physics. I was desperate for the off chance someone could do something for me! A projectile is launched from an initial position of r = (0,0,30)m with an initial velocity vector of v = <4,4,50> m/s. What is the angle between the projectile velocity and the +Z axis at impact?
Well, the velocity at time t is v(t) = <4,4,50-gt> and the position is r(t) = (4t, 4t, -gt^2/2 + 50t + 30) Now I assume 'impact' is when z(t) = 0, the z component of the displacement r. Solve then for t and put that back into the expression for v(t). Finally, the find the angle between v(t) and the z-axis, use the dot product.
since you are giving initial then you are giving position at r(0)
i think i have found something that you first have to integrate your velocity
It was by integrating velocity we arrive at the function r(t)
@salem: Yes, that initial is the position at r(0), I just wasn't entirely sure if I should actually write that. And James, thank you for putting me on the right track!
you should put it in term of vectors actually
same difference.
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