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Mathematics 22 Online
OpenStudy (anonymous):

The data represents the mpg for vehicles manufactured by a company in the past 5 years. Find the third quartile, Q3, of the data. Data: 28.7, 25.5, 21.8, 21.6, 20.5, 16.7, 16.3, 15.4, 13.9. A. 21.8 B. 25.5 C. 24.75 D. 23.65

OpenStudy (anonymous):

OK. First put all the numbers in order.

OpenStudy (anonymous):

So like starting from least to greatest right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

Okay. I got that done: 13.9, 15.4, 16.3, 16.7, 20.5, 21.6, 21.8, 25.5, 28.7.

OpenStudy (anonymous):

ok, great. Does your book tell you how to compute quartiles, by the way? There isn't universal agreement on it. I can tell you how wikipedia says to do it, but it may not be the same as what your book says.

OpenStudy (anonymous):

I don't have a book.

OpenStudy (anonymous):

oh, where did the problem come from?

OpenStudy (anonymous):

A worksheet. I forgot the book.

OpenStudy (anonymous):

oh. Well, anyway, quartiles are what you get when you divide your list of data into 4 parts

OpenStudy (anonymous):

So the 3rd quartile starts 3/4 of the way through the list.

OpenStudy (anonymous):

So what you do to find the 3rd quartile is multiply the length of the list by 3/4, round up, and take that element of the list.

OpenStudy (anonymous):

Ah I'm still confused :/ Can you give me an example, please?

OpenStudy (anonymous):

Well let's take a simple list, 1 2 3 4 5 6 7 8 9. Going 1/4 of the way through the list, is 1/4 * 9 = 2.25, round up to 3. So the third element of the list (3) is the first quartile.

OpenStudy (anonymous):

If the list is 100 200 300 400 500 600 700 800 900, you do the same thing. To find the 3rd quartile, you multiply the length of the list (9) times 3/4, and round up. You get 7. So the 3rd quartile is the 7th element of the list, which is 700.

OpenStudy (anonymous):

So is it basically taking the last number and multiply that by 3/4 and then rounding the answer for that? Or did I understand that completely wrong?

OpenStudy (anonymous):

well, not the last number, but the length of the list.

OpenStudy (anonymous):

My first example was confusing - look at the second example (100 200 300...). In that case there are 9 elements in the list, so to find the 3rd quartile you multiply 3/4 * 9 and round up.

OpenStudy (anonymous):

So counting how many numbers there are and take that and multiply it by 3/4? Or is that still wrong? I'm sorry, I get so confused when it comes to Algebra and Geometry and related things.

OpenStudy (anonymous):

yep, you got it this time

OpenStudy (anonymous):

so now try that on your original list.

OpenStudy (anonymous):

Alright so I took 3/4*9 and I got 6 3/4. I don't think that is right.. it doesn't seem like it.

OpenStudy (anonymous):

nope, that's exactly right ... now round that up to 7, and take the 7th element of the sorted list.

OpenStudy (anonymous):

So 21.8?

OpenStudy (anonymous):

Yep, you got it!

OpenStudy (anonymous):

Thank you! :)

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