Can someone please help me answer this question
A tetrahedral die has 4 faces, number 1-4. If the die is weighted in such a way that each number is twice as likely to land facing down as the next number (1 twice as likely as 2, 2 twice a likely as 3, and so on. What is the probability distribution for the face landing down?

Question

zarkon · Answer

Let D= die roll

start with $$P(D=4)=p$$

work your way backwards to D=1....writing the probability in terms of p

then use the law of total probability to determine the value of p.

anonymous · Answer

weel i got 2 answer i did 1680/8=210 and 6*12*4=24/4=6

zarkon · Answer

those are not probabilities

zarkon · Answer

the probability D is 3 is twice the value of prob D=4 so 

$$P(D=3)=2p$$