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OpenStudy (anonymous):

lim s->0 (1+4s)^1/s

OpenStudy (anonymous):

I don't know what to do!. 1^0 is not an indeterminant form? Anybody please!??!

OpenStudy (anonymous):

=1/(1+4s)^s =1/(1+4(0))^0 =1

OpenStudy (anonymous):

=1/(1+4s)^s =1/(1+4(0))^0 =1

OpenStudy (nikvist):

\[\lim_{s\rightarrow 0}(1+4s)^{1/s}=\lim_{s\rightarrow 0}\left[(1+4s)^{1/4s}\right]^4=\left[\lim_{s\rightarrow0}(1+4s)^{1/4s}\right]^4=e^4\]

OpenStudy (anonymous):

Wow... nikvist is right

OpenStudy (anonymous):

The other two were wrong...

OpenStudy (anonymous):

WHy are they other 2 wrong?

OpenStudy (jamesj):

Nikvist is exactly right, because \[ \lim_{x \rightarrow \infty} (1 + 1/x)^x = \lim_{x \rightarrow 0+} (1+x)^{1/x} = e \]

OpenStudy (jamesj):

the other two are wrong because they're applying a naive procedure that moves taking the limit inside functions (in this case exponential by the variable) which are simply false. The fact that those results are not equal to the correct result demonstrate that the procedure they're using is mathematically invalid.

OpenStudy (anonymous):

Wouldnt x->0 (1+x)^1/x=1, bc 1^infinity=1??

OpenStudy (anonymous):

You're awesome by the way, I can't thank you enough for the help!

OpenStudy (jamesj):

No, because implicit in what you've done is you've said \[ \lim_{x \rightarrow 0} (1+x)^{1/x} = ( \lim_{x \rightarrow 0} (1+x) )^{\lim_{x \rightarrow 0} 1/x} \] and that's just not valid.

OpenStudy (anonymous):

hmm, I don't understand what nikvist did in his first step. How did he get the exponent to 1/4s, and then why is their another exponent 4.

OpenStudy (jamesj):

Call the initial expression f(x). Then he just wrote that \[ ( \ (f(x))^{1/4} \ )^4 \]

OpenStudy (anonymous):

So he just added an exponent, just because? That still doesn't explain were he got the 1/4s instead of just 1/4 as an exponent

OpenStudy (jamesj):

\[ (1+4s)^{1/s} = ( (1+4s)^{1/s} )^{(1/4).4} = ([ (1+4s)^{1/s} ]^{(1/4)} )^4 = ((1+4s)^{1/4s})^4 \]

OpenStudy (anonymous):

Rule of exponents question, when simplifying x^2^3, do you do 3*2 or 3+2?

OpenStudy (anonymous):

I think it's multiply, that would explain the 1/s * 1/4=1/4s. Okay I get it now. So the trick is to realize e=(1+x)^1/x Man that was tricky. I don't know if i would have realized that I needed to pull out the 4 from 4/4.

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