What is the standard form equation of the line passing through (3, –2) with a slope of three-fifths?

Question

anonymous · Answer

y-b=m(x-a)     a= 3 b = -2 m =3/5

anonymous · Answer

y-(-2)=3/5(x-3)
=5(y+2)=3(x-3)
=5y+10=3x-15
<=>3x-5y-25=0 or equivolently 3/5x-y-5=0

anonymous · Answer

y=mx+b which means,  nevermind.. lol I see they have it.

anonymous · Answer

-2=3/5(3) +b

anonymous · Answer

Ullere thank u for helping but where did you get the 5 from?

anonymous · Answer

Which 5?

anonymous · Answer

3/5 is what u gave as a slope

anonymous · Answer

$$y-(-2)=\frac{3}{5}(x-3)$$

anonymous · Answer

ooh never mind you divided both sides by 5 to get the 5 in the second line?

anonymous · Answer

$$y+2=\frac{3}{5}x-\frac{9}{5}$$

anonymous · Answer

$$5y+10=3x-9$$$$3x-5y-19=0$$

anonymous · Answer

Yeah, you said standard form and sometimes those questions are snippy and it being x-y+c=0 or y=mx+c etc. They are the same either way.

anonymous · Answer

Woah sarah is right. I made 3*3 = 15, silly mistake.

anonymous · Answer

y-(-2)=3/5(x-3) =5(y+2)=3(x-3) =5y+10=3x-9 <=>3x-5y-19=0 or equivolently 3/5x-y-19/5=0