Express the equation in the logarithmic form of logC=D. (That is, the logarithm is base 10)

Question

anonymous · Answer

$$10^{-5}=e-5$$

anonymous · Answer

So what are the values of C and D based on $$\log_{10}C=D $$

anonymous · Answer

$$\log_{10}(e-5) = -5 $$

anonymous · Answer

The value (e-5) is not the correct value of C.

turingtest · Answer

o-0
it should be...

anonymous · Answer

Common logs with an exponential?

log10(10^-5)=log(e^-5)
loga(a)=1
1(-5)-log(e^-5)
-5=loge^-5

anonymous · Answer

I know.
But the website says its wrong.

turingtest · Answer

is it really e-5 on the right?

turingtest · Answer

not e^(-5) as suggested above?

anonymous · Answer

The equation on the website is$$10^{-5}=1e-05$$

anonymous · Answer

well then that changes a bit...

turingtest · Answer

0.5
?

anonymous · Answer

I don't know why there is a 0 in front of the 5

anonymous · Answer

the 1e - 05 is calculator notation for 10^(-5) [rather sloppy notation for it]

turingtest · Answer

Oh! lol

anonymous · Answer

so we have$$\log_{10}(10^{-5}) = -5 $$

anonymous · Answer

Ah that makes much more sense.

anonymous · Answer

Thanks a lot! I was so confused

anonymous · Answer

You know as I put down log10(e−5)=−5 to begin with I thought to myself, well that's not right as e-5 is negative and you can't have a log of a negative number.