Evaluate the following limit:

lim x- -4 (2x^2 + 7x - 4)/ (x^2+7x+12)

Answer = 7

Thanks.

@Mathematics

Question

Evaluate the following limit:

lim x-> -4              (2x^2 + 7x - 4)/ (x^2+7x+12)

Answer = 7

Thanks.

@Mathematics

anonymous · Answer

I tried simplifying and then plugging -4 but i keep getting a fraction :S

anonymous · Answer

$$\frac{2x^2 + 7x - 4}{x^2+7x+12}=\frac{(x+4)(2x-1)}{(x+3)(x+4)}=\frac{2x+1}{x+3}$$
I hope you can do it now yourself

agreene · Answer

did you type this correctly? because the answer isnt 7...
It's 9.
Use l'Hopital's rule.

anonymous · Answer

$$\frac{2\cdot(-4)+1}{-4+3}=\frac{-8+1}{-1}=7$$

anonymous · Answer

Yeah I think I typed it out right, thanks a lot for your help Tomas & Agreene, I appreciate it.

agreene · Answer

anonymous · Answer

Oh thats weird :S

agreene · Answer

I call shenanigans on this question!

anonymous · Answer

lol, i made mistake that's why i got 7... sorry, maybe it's correct version of this :DD

anonymous · Answer

Haha wait, I think you're right, it should be 2x-1 / x+3

anonymous · Answer

So then -8-1/-4+3 then = 9 :D

anonymous · Answer

I guess I have a retarded answer sheet

agreene · Answer

oh, i didn't spot that either!
no shenanigans, just two methods to solve ^_^

anonymous · Answer

:D