Question

here we go again lol: 5/x + 4/x-3 =1

A quadratic! please please please help me, thanks so much!!! :)

Answer 1

is this
\[\frac{5}{x}+\frac{4}{x-3}=1\]?

Answer 2

yup :)

Answer 3

\[5(x-3)+4x=x(x-3)\]
\[x^2-12 x+15 = 0\]
then the quadratic formula

Answer 4

do you know the formula? i cant find my paper :(

Answer 5

you can find it on line in many places, for example http://www.sosmath.com/algebra/quadraticeq/quadraformula/quadraformula.html

Answer 6

okay

Answer 7

do you know how to use it?

Answer 8

can someone factor this for me, show me how to do it that way, please

Answer 9

instead of the quadratic formula?

Answer 10

it does not factor. you have to use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Answer 11

that is it does not factor using integers.

Answer 12

satellite: wait a second for her to reply

Answer 13

you can complete the square as follows
\[x^2-12x=-15\]
\[(x-6)^2=-15+36=21\]
\[x-6=\pm\sqrt{21}\]
\[x=6\pm\sqrt{21}\]

Answer 14

ok just a moment....

Answer 15

that looks right, but it wants another # with the 6

Answer 16

nevermind, it took it, thanks!!!!! :D :D