write an equadratic equation for the variable x having -sqrt5,3sqrt5 as the solution

Question

anonymous · Answer

$$-\sqrt{5},  3\sqrt{5}$$

akshay_budhkar · Answer

if a and b are the solutions of a quadratic equation then the equation is given by (x-a)(x-b)=0

So you can substitute a and b and simplify, can you do that?

anonymous · Answer

oh i have to use ax62+bx+c=0

anonymous · Answer

ax^2+bx+c=0

akshay_budhkar · Answer

Nope, that are different a and b.. whjat i am talking of are different

akshay_budhkar · Answer

um. you get it?

anonymous · Answer

start with 
$$(x-\sqrt{5})(x-3\sqrt{5})=0$$ then multiply out. it will be messy

anonymous · Answer

oops that was wrong. start with 
$$(x+\sqrt{5})(x-3\sqrt{5})=0$$

anonymous · Answer

$$x ^{2}-3\sqrt{5}+\sqrt{5x}-3\sqrt{5}$$ is tht it?

jhonyy9 · Answer

from the second term you have missed the x and the last term will be -3*5=-15
 so and now i see that again the 3rd term is wrong because x not is inside radical this will be xsqrt5 right,correct 
- hope that you will can understanding