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Mathematics 19 Online
OpenStudy (anonymous):

Q1. Suppose that four regular 6-sided dice are flipped. 1.What is the probability of a "three-of-a-kind" that is, three of the dice show the same number and the other die shows a different number? 2. What is the probability that at least two of the dice show the same number?

OpenStudy (anonymous):

Hi there! I'd like to help you understand how to do this.

OpenStudy (anonymous):

yes please

OpenStudy (anonymous):

you there

OpenStudy (anonymous):

OK, let's start a little simpler, what if there are only two dice?

OpenStudy (anonymous):

Can you compute the probability they show the same answer?

OpenStudy (anonymous):

less probability

OpenStudy (anonymous):

well how can we quantify it? Hint: the first die will be some number, it doesn't matter what; what's the probability the second die comes up the same?

OpenStudy (anonymous):

(1,1) (2.2) and so on \

OpenStudy (anonymous):

well those are possible outcomes, but we're trying to compute probability. Let me try another way, what's the probability, if you roll a single die, that it comes up with a 1?

OpenStudy (anonymous):

1/6

OpenStudy (anonymous):

great. so if you have two dies, it doesn't matter what the first one is -- what's the probability that the second will be the same?

OpenStudy (anonymous):

two die 2/12

OpenStudy (anonymous):

well, yes, although i'm not sure you got there quite right - basically the first die will have some value. no matter what that value is, the second die will have a 1/6 chance of coming up the same. does that make sense?

OpenStudy (anonymous):

pardon

OpenStudy (anonymous):

yes?

OpenStudy (anonymous):

what do you mean

OpenStudy (anonymous):

okay, you roll the first die, it comes up with some number -- 4, 2, 1, it doesnt matter what. then you roll the second die. what's the probability that this second die will come up the same as the first?

OpenStudy (anonymous):

1/6

OpenStudy (anonymous):

i guess

OpenStudy (anonymous):

two separate occassion

OpenStudy (anonymous):

nice! Okay so let's do three now. You roll the first die. It comes up, say, a 3. What's the probability the second AND third dice both come up a 3?

OpenStudy (anonymous):

did i say correct bfr

OpenStudy (anonymous):

3/18

OpenStudy (anonymous):

nope. two events that are independent, you multiply the probabilities.

OpenStudy (anonymous):

2/12

OpenStudy (anonymous):

let me try this a different way. Imagine you roll two dice, what's the probability that the first one comes up 5, AND, the second one comes up 2?

OpenStudy (anonymous):

5/6 , 2/6

OpenStudy (anonymous):

are you saying the probability of a die coming up with 5 is different than the probability it will come up as, say, a 4?

OpenStudy (anonymous):

can u cvlear the concept you r mkin more complicated for me i guess

OpenStudy (anonymous):

well everything we're talking about so far is much simpler than the actual question you asked

OpenStudy (anonymous):

ok, let me try this.. if you roll a single die, what's the probability that what will come up is a 5?

OpenStudy (anonymous):

1/6

OpenStudy (anonymous):

OK, and what's the probability that what will come up is a 2?

OpenStudy (anonymous):

2/6

OpenStudy (anonymous):

why 2/6?

OpenStudy (anonymous):

the probability of any number coming up is the same, right?

OpenStudy (anonymous):

ya ohh yes so then

OpenStudy (anonymous):

okay so what's the probability of a die coming up 2?

OpenStudy (anonymous):

1/6

OpenStudy (anonymous):

would be same

OpenStudy (anonymous):

ok, and a probability of it coming up a 5?

OpenStudy (anonymous):

1/6

OpenStudy (anonymous):

great. so what's the probability that we roll two at the same time, and the first one comes up 2, and the second comes up 5?

OpenStudy (anonymous):

2/12

OpenStudy (anonymous):

why?

OpenStudy (anonymous):

outcome will double

OpenStudy (anonymous):

2/12 is the same as 1/6 isn't it?

OpenStudy (anonymous):

and 6+6

OpenStudy (anonymous):

what do you mean by "outcome wil double"?

OpenStudy (anonymous):

6+6

OpenStudy (anonymous):

no. If two things happen independently, you *multiply* the probability of the individual events to find the probability that they both happen.

OpenStudy (anonymous):

2/36

OpenStudy (anonymous):

closer. you're multiplying 1/6 times 1/6

OpenStudy (anonymous):

what's 1/6 times 1/6?

OpenStudy (anonymous):

why

OpenStudy (anonymous):

you said 2/36, that's not correct

OpenStudy (anonymous):

if two events happen independently, then the probability that they *both* happen is the individual probabilities, multiplied.

OpenStudy (anonymous):

then

OpenStudy (anonymous):

2/12

OpenStudy (anonymous):

so if one die has a 1/6 chance of coming up 2, and a second die separately has a 1/6 chance of coming up 5, then the probability that this both happens -- i.e. that you roll two dice, and they come up 2 and 5, is....?

OpenStudy (anonymous):

OK, can you do the following math problem: \[{ 1 \over 6} x {1 \over 6 }\]

OpenStudy (anonymous):

it is not 2/12 and not 2/36

OpenStudy (anonymous):

1/36

OpenStudy (anonymous):

is it ok now

OpenStudy (anonymous):

OK, yes. Nice. Now, what's the probability if you roll *three* dice, that the first comes up 5, and second comes up 2, and the third comes up 4?

OpenStudy (anonymous):

1/216 i guess if iam not wrong

OpenStudy (anonymous):

yes, you got it!

OpenStudy (anonymous):

ok now we're going to do something a little different. What's the probability you roll a single die, and it comes up with any number *except* for 4?

OpenStudy (anonymous):

we're getting closer to your final answer

OpenStudy (anonymous):

1/5

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

confusing

OpenStudy (anonymous):

1/6-1/4

OpenStudy (anonymous):

is it ok now

OpenStudy (anonymous):

r u there

OpenStudy (anonymous):

helllo

OpenStudy (anonymous):

hi sorry

OpenStudy (anonymous):

what's the probability that 1, 2, 3, 4, or 6 comes up? i.e., any number except 5? there are 5 ways this can happen out of the 6 ways a die can come up.

OpenStudy (anonymous):

hello?

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

r u there now

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