Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

How to solve this equation with partial differentiation !

OpenStudy (anonymous):

OpenStudy (anonymous):

sorry dude.... incorrect questions so according to your questions all the answers are 0

myininaya (myininaya):

I'm assuming E is a function of z and t

myininaya (myininaya):

should i assume this iwanbah?

OpenStudy (anonymous):

@myininaya u can't change the question dude

myininaya (myininaya):

i'm not changing the question

myininaya (myininaya):

i'm asking for details

OpenStudy (anonymous):

yes, E is a function of z and t

myininaya (myininaya):

Pretend we have \[f(x,y)=xy => f_x=y \text{ & } f_y=x\] \[E(z,t)=\frac{G(z,t)}{F(z,t)}\] \[E_z=\frac{G_zF-F_zG}{F^2}\]

myininaya (myininaya):

\[E_t=\frac{G_tF-F_tG}{F^2}\]

myininaya (myininaya):

\[E_{ t t}=\frac{(G_tF-F_tG)_tF^2-(F^2)_t(G_tF-F_tG)}{F^4}\] \[=\frac{[G_{t t}F+G_tF_t-(F_{t t} G+F_tG_t)]F^2-2FF_t(G_tF-F_tG)}{F^4}\] \[=\frac{[G_{ t t}F-F_{t t } G]F^2-2F^2F_tG_t+2F(F_t)^2G}{F^4}\] \[=\frac{G_{ t t} F^3-F^2 F_{t t} G-2F^2F_tG_t+2F(F_t)^2G}{F^4}\]

OpenStudy (anonymous):

Thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!