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OpenStudy (anonymous):

Solving rational equations: (2x+2) (4x^2-16) (5x-5) ------- - ---------- = -------------- (3x-12) (3x^2-24x+48) (3x^2-24x+48) I have the answer already, but I don't know how it came to be I try to do it by factoring the 3x^2-24x+48 's and get 3(x^2-8+16) then I multiply that by everything, as with the other denominators, and so on but then I get a huge, incorrect answer Someone please help even if it's one sentence. I want to get this problem done by tonight

OpenStudy (anonymous):

Firstly you can factor out a 3

OpenStudy (anonymous):

and then it becomes 3(x-4)^2

OpenStudy (anonymous):

and 3x-12 can also be factored

OpenStudy (anonymous):

3(x-4)

OpenStudy (anonymous):

So from what I see in order to get the same denomanator you must multiply the denomanator and numerator by (x-4)

OpenStudy (anonymous):

Did u get that so far

OpenStudy (anonymous):

yes and i'm fixing it on my paper... stupid factoring mistakes Thanks!

OpenStudy (anonymous):

ok gnite

OpenStudy (anonymous):

after this problem goodnight

OpenStudy (anonymous):

Do you multiply the numerator of the first fraction by 3(x-4)^4? This is where i messed up the most I was struggling with factoring because I'm half asleep if you were wondering why I took so long by the way...

OpenStudy (anonymous):

nope you multiply the numerator and the denomanator of the first term by (x-4)

OpenStudy (anonymous):

what about the 3?

OpenStudy (anonymous):

because in the second fraction the denominator I get is 3(x-4)

OpenStudy (anonymous):

well we already have a 3 in the denomanator of the first term

OpenStudy (anonymous):

First term denomanator: 3(x-4) second term denomanator: 3(x-4) (x-4)

OpenStudy (anonymous):

so all your missing in the first term is the (x-4)

OpenStudy (anonymous):

how did you get rid of the 3?

OpenStudy (anonymous):

I factored it

OpenStudy (anonymous):

factor (3x-12) for me

OpenStudy (anonymous):

3(x-4)

OpenStudy (anonymous):

it is 3(x-4)

OpenStudy (anonymous):

ya

OpenStudy (anonymous):

so what doesn't make sense

OpenStudy (anonymous):

when you're supposed to multiply everything by the denominator

OpenStudy (anonymous):

nope we have two denomanators and we need them to be the same

OpenStudy (anonymous):

so in order ofor 3(x-4) to be equal to 3(x-4)^2

OpenStudy (anonymous):

we would have to multiply the first term by a (x-4)

OpenStudy (anonymous):

so 3(x-4)*(x-4)=3(x-4)^2

OpenStudy (anonymous):

Is that clear?

OpenStudy (anonymous):

yes sort of , do we do that to the numerator too?

OpenStudy (anonymous):

yup forsure

OpenStudy (anonymous):

ooooooooooooooooooooooooooooohhhhhhhhhhhhhhhhhhhhhhhhhhhhhh ok I see I see

OpenStudy (anonymous):

YAY i am so excited

OpenStudy (anonymous):

I try to explain concepts but sometimes the person on the other end can't understand

OpenStudy (anonymous):

THANK YOU OK I ACTUALLY SEE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! THANK YOU OK LISTEN TO ME RIGHT NOW LOOK AT YOURSELF IN THE MIRROR AND SAY HELL YEAH IM AWESOME IM SO GOOD AT MATH THANK YOU OKAY BECAUSE I WAS REALLY STRUGGLING WITH THAT AND NOW I CAN FINALLY SLEEP

OpenStudy (anonymous):

NOW IM GOING TO FINISH THIS PROBLEM AND GET THE RIGHT ANSWER!!!!!!!!!!

OpenStudy (anonymous):

Oh thanks for the boost I needed that one!!! LOL

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

someone give rld613 some more medals

OpenStudy (anonymous):

i'm going to solve this problem right now afk

OpenStudy (anonymous):

I am really not into the medal thing

OpenStudy (anonymous):

I just enjoy doing math

OpenStudy (anonymous):

its like past 2 am and I am still doing math equations!!! I shld be long in bed

OpenStudy (anonymous):

K now that we finished i am going to bed

OpenStudy (anonymous):

rld are you still there?

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