Question

In the problem of "e^(x)-e^(-x)=2", how do you get to here, "e^(2x)-2e^(x)-1=0".

Answer 1

us ln on both sides

Answer 2

2 will be 2lne what signe ln(e)2 logarithm natural from e on exponent 2

Answer 3

just convert e^-x as 1/e^x
we have
e^x-1/e^x=2
multiplying whole equation by e^x
we get
e^2x-1=2e^x
so we get
e^2x-2e^x=1

Answer 4

blah thats what I did I just messed up the last step thanks :D

Answer 5

so but if you need to solve it you need to us what i have wrote before

Answer 6

No to solve it you need to use the quadratic formula

Answer 7

CP is exactly right.