Question

Multiply and simplify radical 3 times the quantity 4+radical 12.
A. the square root of 12+6
B. 4 and the square root of 3+6
C. 2 and the square root of 3+6 and the square root of 3

Answer 1

\[\sqrt{3(4 +}\sqrt{12)} \] is the equation. The answer choices are:

A. \[\sqrt{12 + 6}\]

B. \[4\sqrt{3+6}\]

C. \[2\sqrt{3+6}\sqrt{3}\]

Answer 2

well let's start by first multiplying the 3 out

Answer 3

How do I do that? :/ Ugh. Math is so confusing for me! Would I multiply it by the 4 or multiply it by itself?

Answer 4

when i am finished with my question I will help u out

Answer 5

Thank you very much :)

Answer 6

ok I am back

Answer 7

\[\sqrt{3(4+\sqrt{12}}\]
first you open the bracket that can be done by multiplying 3*(4+sqrt12)
that's 12+3*sqrt12

Answer 8

Alright sweet :) What should I do for this problem?

Answer 9

wait I am gonna figure it out

Answer 10

now see it's \[\sqrt{12+\sqrt(12)}\]
NOW 12=4*3
SO WE HAVE SQRT(12+SQRT(4*3))
2 IS THE SQUARE ROOT OF 4 SO IT CAN BE TAKEN OUT OF THE RADICAL
NOW WE HAVE
\[\sqrt(12+2\sqrt(3))\]

Answer 11

the answer is c

Answer 12

Do u want an expalnation

Answer 13

I won't bite

Answer 14

meow i think the question is
\[\sqrt(3)(4+\sqrt(12))\]

Answer 15

But c makes sense

Answer 16

with the way she originally wrote it

Answer 17

No that's how it says. The way I wrote it.

Answer 18

so we'll get \[4\sqrt(3)+\sqrt(3)\sqrt(12)\]
next we'll multiply sqrt(3) and sqrt(12)
we'll get sqrt(36) ie.6
\[4\sqrt(3)+\sqrt(36)\]
we get \[4\sqrt(3)+6\]