Question

A road has a hump 10 m in radius. What is its minimum speed at which a car will leave the road at the top of the hump?

Answer 1

the car leaves at the top when the centipetal force exceeds acceleration due to gravity v^2/r> 10m/s^2 v>10m/s

Answer 2

For this to occur, gravity must be weaker than the centripetal force required to keep the car going along the radius of the circle.\[\frac{mv^2}{r}>mg \Rightarrow \boxed{v>\sqrt{rg}}\]

Answer 3

kahirap ng project ni sir bayan noh...
tsk tsk tsk....

Answer 4

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