Question

From the top of a cliff, the angle of depression to a boat out in the water is 28 degrees. If the boat is 750 feet away from the bottom of the cliff, how high is the cliff off the ground?

Answer 1

Angle of depression equals the angle of the elevation from the boat's point of view.\[\text{height}=750 \tan (28 {}^{\circ})=398.8 \text{ feet} \]

Answer 2

we know perpendicular /base=sin theta
theta=28
p=750
b=?
so sin 28=750/b
b=750/sin(28)
b=1597.7844 meters that's the height of the cliff