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Mathematics 11 Online
OpenStudy (anonymous):

simplify: [(11 to the second)to the fifth]to the third

OpenStudy (asnaseer):

\[((11^2)^5)^3\]to do this make use of the rule:\[(x^a)^b=x^{ab}\]

jimthompson5910 (jim_thompson5910):

\[\Large ((11^2)^5)^3\] \[\Large (11^2)^{5*3}\] \[\Large (11^2)^{15}\] \[\Large 11^{2*15}\] \[\Large 11^{30}\]

OpenStudy (anonymous):

I understand this, but can I leave it \[11^{30}\] is this simplified?

OpenStudy (asnaseer):

yes

OpenStudy (anonymous):

I'd give you another medal, but it won't let me. Thanks.

OpenStudy (asnaseer):

:-) no worries - I am glad I could help you - that is reward enough

jimthompson5910 (jim_thompson5910):

You can evaluate \[\Large 11^{30}\], but that number is waaaaay too big (the final result has 32 digits). Of course, you can use scientific notation, but leaving it as \[\Large 11^{30}\] is just fine.

OpenStudy (anonymous):

Okay! That's what I was unsure of. I could get to 11^{30}, but then I wasn't sure if I actually needed to calculate the answer. Thank you both!!! I'm a fan of both now.

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