Question

I guys i have a question on this COMPLETING THE SQUARE :

solve by completing the square;
y=6x^2-7x+2

Answer 1

yup your gonna have to complete the square and work with some fractions

Answer 2

i plugged it in the calculator the answer is 38 y=38

Answer 3

so far i am stuck because

Answer 4

\[(x-\frac{7}{12})^2=\frac1{144}\]
is your completed square.
\[x=\frac12; \space x=\frac23\]

Answer 5

okay this is what i have so far:
0=6x2-7x+2
-2=(7/2)^2=6x^2-7x+9(7/2)^2

Answer 6

do you have a scientific calculator ?

Answer 7

no i have to show my work

Answer 8

and I need help on HOW you get there, not just the answer

Answer 9

I rather hate typing out steps with fractions--but wolfram did it just as I did.
Click show steps on the right.
http://www.wolframalpha.com/input/?i=0%3D6x%5E2-7x%2B2+solve

Answer 10

what is the perfect share of 6x^2-7x+49/4

Answer 11

* sqare

Answer 12

(49/4)

Answer 13

that isnt going to factor to something useful.

Answer 14

i know that's why i am stuck

Answer 15

no i know how to do it but that just stumped me

Answer 16

Well, if you click the link I gave, and then show steps under results... you'll see the way I did it. I just seriously hate typing fractions on here.

Answer 17

okay dude i knpow how to do completing the squares in general

Answer 18

and 6x^2-7x+49/4 factors to:

1/4 (24 x^2-28 x+49)

Answer 19

JUST ! stumped me because there is no perfect sqare for 6x^@-7x+(49/4)

Answer 20

thank you

Answer 21

you are going to have to divide by6 as step one. you cannot complete the square if the leading coefficient is not 1

Answer 22

humm?

Answer 23

also i note that this says

solve by completing the square;
y=6x^2-7x+2

this is not clear. you can "solve"
\[6x^2-7x+2=0\] or you can "complete the square" and rewrite
\[y=6x^2-7x+2\] as
\[y=6(x-\frac{7}{12})^2-\frac{1}{24}\]

Answer 24

where did the 12 and 24 xcome from

Answer 25

if the question is
"solve"
\[6x^2-7x+2=0\] by completing the the square you are justified in dividing by 6 because you have an equation to solve. start with
\[6x^2-7x=-2\] then

\[x^2-\frac{7}{6}x=-\frac{1}{3}\]

Answer 26

i thought it would be 2/3

Answer 27

on the right side of the 7/6 thing

Answer 28

now half of \[\frac{7}{6}\] is
\[\frac{7}{12}\] so next step is
\[(x-\frac{7}{12})^2=-\frac{1}{3}+\frac{49}{144}\]

Answer 29

now a step of arithmetic gives
\[(x-\frac{7}{12})^2=\frac{1}{144}\] and then
\[x-\frac{7}{12}=\frac{1}{12}\] or
\[x-\frac{7}{12}=-\frac{1}{12}\]

Answer 30

finally
\[x=\frac{8}{12}=\frac{2}{3}\] or
\[x=\frac{6}{12}=\frac{1}{2}\]

Answer 31

and that is all the gory complete square details

Answer 32

okay ummm thanks

Answer 33

if not clear let me know but i think all the details are written out without any thing missing

Answer 34

yw