Question

Its a log problem which has sqrt so i shall post in reply...

Answer 1

\[\log_{4} \sqrt[4]{32\sqrt[3]{16\sqrt{64.8^{-3\div4}}}}\]

Answer 2

2^5 = 32
2^4 = 16
Is it 64 x 8? or 64.8

Answer 3

its 64 x 8^-3/4

Answer 4

please give full explanation

Answer 5

2^3 = 8
2^6 = 64
Now try it

Answer 6

I don't like this problem

Answer 7

wait even i dont like it

Answer 8

It's not hard but it's unnecessary

Answer 9

its necessary for me

Answer 10

1.019

Answer 11

i am not getting it can u xplain

Answer 12

oh cool sheg

Answer 13

no sheg answer is wrong

Answer 14

how come plz explain m right

Answer 15

idk answer given as 121/186 or 0.6505376

Answer 16

ok wait i made one mistake now i got it

Answer 17

I am getting .7 after simplifying and calculating it in the calculator

Answer 18

do not use claculator

Answer 19

and explain

Answer 20

u should get it as 121/186

Answer 21

King It's a big waste of time, it's not worth it

Answer 22

pls ishaan its necessary fr me

Answer 23

sheg wat abt u?

Answer 24

trying to solve it manually

Answer 25

Hmm I am not posting the complete solution, Just a little simplification

\[\frac{1}{4} \left(\log_4 32 + \frac{1}{3}\left(\log_416 + \frac{1}{2}\left(\log_4 64 + \log_4 8^{\frac{-3}{4}} \right)\right)\right)\]

Answer 26

is that 64 times 8?????????????

Answer 27

Now you should do it on your own, I really don't like calculating Numbers

Answer 28

how did u get 1/4

Answer 29

yeah sheg

Answer 30

oh got i was taking 64.8

Answer 31

Yeah Sheg

Answer 32

Read the FIITJEE Module for Logs it's the basic property of Log

Answer 33

nahi yar mein usko decimal mein le raha tha na bracket use kiya hai isne na kuch

Answer 34

wait im reading and i gave u this sum from FIITJEE compendium

Answer 35

sry sheg are u now getting right answer?

Answer 36

Hmm mujhe bhi same confusion hua tha

Answer 37

i m getting this thing

\[\log_{4} 2^{\frac{167}{96}}\]

Answer 38

what is that 2^?

Answer 39

167/96

Answer 40

thats 0.8 sumthing...

Answer 41

ishaan i calculated ure equation i got 29/32

Answer 42

you must have calculated it wrong

Answer 43

wait i am checking for mistake

Answer 44

I am getting 127/192 I hate this problem, I hate calculating numbers

Answer 45

.661458333 <<Calculator

Answer 46

u need to subtract 6 frm numerator and denom. to get rite answer so thatt means u are very close

Answer 47

Took me forever to get to the bottom of this >.>

Answer 48

so post solution katrina

Answer 49

ishaan what is simplified version of log8^-3/4 base4

Answer 50

\[\log_4\sqrt[4]{32\sqrt[3]{16\sqrt{64\cdot8^{-\frac{3}{4}}}}}=\]
\[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\sqrt{2^6\cdot2^{-\frac{9}{4}}}}}=\]
\[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\sqrt{2^{\frac{15}{4}}}}}=\]
\[\log_4\sqrt[4]{2^5\sqrt[3]{2^4\cdot{2^{\frac{15}{8}}}}}=\]
\[\log_4\sqrt[4]{2^5\sqrt[3]{{2^{\frac{47}{8}}}}}=\]
\[\log_4\sqrt[4]{2^5\cdot{{2^{\frac{47}{24}}}}}=\]
\[\log_4\sqrt[4]{{{2^{\frac{167}{24}}}}}=\]
\[\log_{2^2}2^{\frac{167}{96}}=\]
\[\log_{2}2^{\frac{167}{192}}=\]
\[\frac{167}{192}\]

Answer 51

Yeah I did it again I am getting the same

Answer 52

can u explain the 4th step

Answer 53

how did u take out 2^15/4?

Answer 54

\[2^4\cdot2^{\frac{15}{8}}=2^{4+\frac{15}{8}}=2^{\frac{32}{8}+\frac{15}{8}}=2^{\frac{47}{8}}\]
this one?

Answer 55

no how did u take 2^15/4 out frm sqrt

Answer 56

http://www.wolframalpha.com/input/?i=log_4%28%2832+*+%2816+*%2864+*+8^%28-3%2F4%29%29^%281%2F2%29%29^%281%2F3%29%29^%281%2F4%29 Tomas Is Right, FIITJEE is wrong!

Answer 57

ok now can u xplain

Answer 58

\[\sqrt{2^\frac{15}{4}}=2^{\frac{15}{4}\cdot\frac{1}{2}}=2^\frac{15}{8}\]

Answer 59

oh right

Answer 60

\[\sqrt[n]{m}=m^{\frac{1}{n}}\]

Answer 61

Yipppeeeeeeeee u guys are great!!!!!!!!!!
thnx to all of u.!!!!!!!!!!!!!!!