Question

derivation
y=x^x*lnx

Answer 1

\[x^{xlnx} OR x^xlnx\]

Answer 2

?

Answer 3

no its x^x multiply lnx

Answer 4

\[\large { x^{xlnx}}\]?

Answer 5

no lalaly

Answer 6

\[\large{x^x} \times lnx\]

Answer 7

?

Answer 8

yes lalaly

Answer 9

you want the derivative of that?

Answer 10

derivative

Answer 11

yes

Answer 12

okay do you know about chain rule ?

Answer 13

yes

Answer 14

what is the derivative of $$x^x$$ ?

Answer 15

\[xx ^{x-1}\]

Answer 16

No, note in x^x the exponent is not a constant but the independent variable itself.

Answer 17

so derivative would be $$ x^x (1+\ln x)$$

Answer 18

ok

Answer 19

Final answer:

$$ x^{x-1}+x^x \ln x(1+\ln x)$$

Answer 20

its not correct

Answer 21

it is correct

Answer 22

I differentiated $$ \large{x^x} \times lnx$$

Answer 23

did you use logarithm?

Answer 24

http://www.wolframalpha.com/input/?i=diff+x%5Ex+*ln%28x%29

Answer 25

(lnx1+ 1/xlnx) x^lnx that is correct

Answer 26

* (lnx1+1/xlnx)x^xlnx

Answer 27

you are not making any sense.

what is x1?

Answer 28

\[y'= (lnx+1+1/xlnx)x ^{x \times}lnx\]

Answer 29

FoolForMath gave you the correct answer for the question you asked.

Answer 30

ok