Write your result in standard form: 3i(4-5i) + 2i(4i-√-25)
which part of this are you stuck on?
I just don't understand where to start.
ok, do you know how to expand each of the bracketed expressions?
I don't :(
ok, lets start from the beginning then. if we have: a(b+c) this means "a" multiplied by the sum of "b" and "c". this gives you "a" lots of "b" and "c", so we can expand this as follows: a(b+c) = ab + ac do you understand this part?
Yes, I do.
e.g.: 3(4+2) = 3*4 + 3*2 = 12 + 6 = 18 we can this as 4+2=6, so 3(4+2) = 3 * 6 = 18
ok, so lets try to expand the first expression: \[3i(4-5i) =3i*4 - 3i*5i=12i-15i^2\]now since \(i=\sqrt{-1}\) we know that \(i^2=-1\), we therefore get:\[3i(4-5i)=12i-15i^2=12i-(15*-1)=12i-(-15)=12i+15\] got that?
yes, i do. the radicals are what confuse me.
ok, so lets look at those nasty radicals next...
in this expression:\[2i(4i-\sqrt{-25})\]the \(\sqrt{-25}\) can be written as follows:\[\sqrt{-25}=\sqrt{25*-1}=\sqrt{25}*\sqrt{-1}=\sqrt{25}*i=5i\]so we can rewrite the original as:\[2i(4i-5i)\]understand so far?
Where did you get the -1? Or do we multiply by that so we can get rid of the negative?
-25 = 25 * -1
any positive number times -1 will give you the negative of that number
Right, I understand that now.
\[2i(4i-\sqrt{-25})=2i(4i-5i)=2i(-i)=2i * -i = -2i^2 = -2 * i^2\]\[= -2 * (-1) = 2\]
does that make sense?
yes.
ok, so finally we put it all together to get:\[12i+15+2=12i+17\]the standard form for a complex number is usually written as:\[a+bi\]where \(i=\sqrt{-1}\) so we can just rearrange the final answer to get:\[17+12i\]
That was a tough one! I'm starting to get the hang of this radical stuff. Thank you so much.
yw - I'm glad I could help you understand.
I'm terrible at this math stuff. I'm glad there are people like you that can help break it down.
have faith in your abilities and you will achieve things you never thought you could. :-)
I will surely remember that :)
take care...
you too! Thank you once again.
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