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Integrate : sinx - sin2x
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-cos(x)+cos(2x)/2
rewrite sin2x as 2sinxcosx
yes, i did that i thought i would have to use substitution
yeah u-sub should take care of it
or better yet, just remember it because math teachers seem to love this one. \[\int\sin(2x)dx=-\frac{1}{2}\cos(2x)\] \[\int \ln(x)dx=x\ln(x)-x\] save you fifteen minutes an exam really
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ok let me see
ill try both ways....la grange, would i take out a sinx once i rewrite the equation?
you could or you could simply write two integrals
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