Sorry, I misphrased the question earlier. What are the four ordered pairs of integers (x , y , z) for which x^3 + y^3 + z^3 = 3?
1 works
It has to be an ordered pair.
(x,y,z) is not an ordered pair
Lol. My bad. I meant ordered triple.
(4,4,-5)
i like my answer too.
i like zarkon's because it seems more sophisticated
jk i like your answer too satellite
i have do doubt that zarkon's answer is more sophisticated. a more interesting question is how many such ordered pairs there are
(4,-5,4) (-5,4,4) are two others lol
cheater
its only cheating if it looks exactly the same
did you get that line from your students?
One last one ... lol.
yes i learn from them
you have your 4
A tougher question is proving there are only 4.
can you prove that james?
or how would you go about proving it
Not quickly, no.
i should say not http://mathoverflow.net/questions/58188/are-nontrivial-integer-solutions-known-for-x3y3z33
If I'd taken number theory sometime in the last decade I could tell you how to approach proving it. But a problem like this is either easy or absurdly hard.
let's assume it is absurdly hard and call it a day ;)
@sat73. Ha, yes. It belongs to the 'absurdly hard' category.
"Of course the problem is old and probably there is no hope to be resolved." i'll get back to you after lunch
Lol ... I can't do proofs.
Anyway ... what's the other question CentSci?
ok lets not worry about it lets not get headaches
Nothing ... I think you got all the triples.
ok
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